3.1134 \(\int \frac{\cot ^4(c+d x) \csc (c+d x)}{(a+b \sin (c+d x))^2} \, dx\)

Optimal. Leaf size=292 \[ -\frac{2 b \left (-7 a^2 b^2+2 a^4+5 b^4\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^6 d \sqrt{a^2-b^2}}-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}-\frac{\left (-36 a^2 b^2+3 a^4+40 b^4\right ) \tanh ^{-1}(\cos (c+d x))}{8 a^6 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))} \]

[Out]

(-2*b*(2*a^4 - 7*a^2*b^2 + 5*b^4)*ArcTan[(b + a*Tan[(c + d*x)/2])/Sqrt[a^2 - b^2]])/(a^6*Sqrt[a^2 - b^2]*d) -
((3*a^4 - 36*a^2*b^2 + 40*b^4)*ArcTanh[Cos[c + d*x]])/(8*a^6*d) - (b*(11*a^2 - 15*b^2)*Cot[c + d*x])/(3*a^5*d)
 + ((13*a^2 - 20*b^2)*Cot[c + d*x]*Csc[c + d*x])/(8*a^4*d) - ((3*a^2 - 5*b^2)*Cot[c + d*x]*Csc[c + d*x]^2)/(3*
a^3*b*d) + ((4*a^2 - 5*b^2)*Cot[c + d*x]*Csc[c + d*x]^2)/(4*a^2*b*d*(a + b*Sin[c + d*x])) - (Cot[c + d*x]*Csc[
c + d*x]^3)/(4*a*d*(a + b*Sin[c + d*x]))

________________________________________________________________________________________

Rubi [A]  time = 1.04726, antiderivative size = 292, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.259, Rules used = {2890, 3055, 3001, 3770, 2660, 618, 204} \[ -\frac{2 b \left (-7 a^2 b^2+2 a^4+5 b^4\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^6 d \sqrt{a^2-b^2}}-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}-\frac{\left (-36 a^2 b^2+3 a^4+40 b^4\right ) \tanh ^{-1}(\cos (c+d x))}{8 a^6 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))} \]

Antiderivative was successfully verified.

[In]

Int[(Cot[c + d*x]^4*Csc[c + d*x])/(a + b*Sin[c + d*x])^2,x]

[Out]

(-2*b*(2*a^4 - 7*a^2*b^2 + 5*b^4)*ArcTan[(b + a*Tan[(c + d*x)/2])/Sqrt[a^2 - b^2]])/(a^6*Sqrt[a^2 - b^2]*d) -
((3*a^4 - 36*a^2*b^2 + 40*b^4)*ArcTanh[Cos[c + d*x]])/(8*a^6*d) - (b*(11*a^2 - 15*b^2)*Cot[c + d*x])/(3*a^5*d)
 + ((13*a^2 - 20*b^2)*Cot[c + d*x]*Csc[c + d*x])/(8*a^4*d) - ((3*a^2 - 5*b^2)*Cot[c + d*x]*Csc[c + d*x]^2)/(3*
a^3*b*d) + ((4*a^2 - 5*b^2)*Cot[c + d*x]*Csc[c + d*x]^2)/(4*a^2*b*d*(a + b*Sin[c + d*x])) - (Cot[c + d*x]*Csc[
c + d*x]^3)/(4*a*d*(a + b*Sin[c + d*x]))

Rule 2890

Int[cos[(e_.) + (f_.)*(x_)]^4*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)
, x_Symbol] :> Simp[(Cos[e + f*x]*(d*Sin[e + f*x])^(n + 1)*(a + b*Sin[e + f*x])^(m + 1))/(a*d*f*(n + 1)), x] +
 (Dist[1/(a^2*b*d*(n + 1)*(m + 1)), Int[(d*Sin[e + f*x])^(n + 1)*(a + b*Sin[e + f*x])^(m + 1)*Simp[a^2*(n + 1)
*(n + 2) - b^2*(m + n + 2)*(m + n + 3) + a*b*(m + 1)*Sin[e + f*x] - (a^2*(n + 1)*(n + 3) - b^2*(m + n + 2)*(m
+ n + 4))*Sin[e + f*x]^2, x], x], x] - Simp[((a^2*(n + 1) - b^2*(m + n + 2))*Cos[e + f*x]*(d*Sin[e + f*x])^(n
+ 2)*(a + b*Sin[e + f*x])^(m + 1))/(a^2*b*d^2*f*(n + 1)*(m + 1)), x]) /; FreeQ[{a, b, d, e, f}, x] && NeQ[a^2
- b^2, 0] && IntegersQ[2*m, 2*n] && LtQ[m, -1] && LtQ[n, -1]

Rule 3055

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*s
in[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> -Simp[((A*b^2 - a*b*B + a^2*C)*Cos[e +
 f*x]*(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^(n + 1))/(f*(m + 1)*(b*c - a*d)*(a^2 - b^2)), x] + Dis
t[1/((m + 1)*(b*c - a*d)*(a^2 - b^2)), Int[(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^n*Simp[(m + 1)*(b
*c - a*d)*(a*A - b*B + a*C) + d*(A*b^2 - a*b*B + a^2*C)*(m + n + 2) - (c*(A*b^2 - a*b*B + a^2*C) + (m + 1)*(b*
c - a*d)*(A*b - a*B + b*C))*Sin[e + f*x] - d*(A*b^2 - a*b*B + a^2*C)*(m + n + 3)*Sin[e + f*x]^2, x], x], x] /;
 FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && Lt
Q[m, -1] && ((EqQ[a, 0] && IntegerQ[m] &&  !IntegerQ[n]) ||  !(IntegerQ[2*n] && LtQ[n, -1] && ((IntegerQ[n] &&
  !IntegerQ[m]) || EqQ[a, 0])))

Rule 3001

Int[((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.)
+ (f_.)*(x_)])), x_Symbol] :> Dist[(A*b - a*B)/(b*c - a*d), Int[1/(a + b*Sin[e + f*x]), x], x] + Dist[(B*c - A
*d)/(b*c - a*d), Int[1/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, A, B}, x] && NeQ[b*c - a*d, 0]
 && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]

Rule 3770

Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]

Rule 2660

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = FreeFactors[Tan[(c + d*x)/2], x]}, Dis
t[(2*e)/d, Subst[Int[1/(a + 2*b*e*x + a*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] &&
 NeQ[a^2 - b^2, 0]

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{\cot ^4(c+d x) \csc (c+d x)}{(a+b \sin (c+d x))^2} \, dx &=\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}+\frac{\int \frac{\csc ^4(c+d x) \left (4 \left (3 a^2-5 b^2\right )-a b \sin (c+d x)-\left (8 a^2-15 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{4 a^2 b}\\ &=-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}+\frac{\int \frac{\csc ^3(c+d x) \left (-3 b \left (13 a^2-20 b^2\right )+5 a b^2 \sin (c+d x)+8 b \left (3 a^2-5 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{12 a^3 b}\\ &=\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}+\frac{\int \frac{\csc ^2(c+d x) \left (8 b^2 \left (11 a^2-15 b^2\right )+a b \left (9 a^2-20 b^2\right ) \sin (c+d x)-3 b^2 \left (13 a^2-20 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{24 a^4 b}\\ &=-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}+\frac{\int \frac{\csc (c+d x) \left (3 b \left (3 a^4-36 a^2 b^2+40 b^4\right )-3 a b^2 \left (13 a^2-20 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)} \, dx}{24 a^5 b}\\ &=-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}-\frac{\left (b \left (2 a^4-7 a^2 b^2+5 b^4\right )\right ) \int \frac{1}{a+b \sin (c+d x)} \, dx}{a^6}+\frac{\left (3 a^4-36 a^2 b^2+40 b^4\right ) \int \csc (c+d x) \, dx}{8 a^6}\\ &=-\frac{\left (3 a^4-36 a^2 b^2+40 b^4\right ) \tanh ^{-1}(\cos (c+d x))}{8 a^6 d}-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}-\frac{\left (2 b \left (2 a^4-7 a^2 b^2+5 b^4\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^6 d}\\ &=-\frac{\left (3 a^4-36 a^2 b^2+40 b^4\right ) \tanh ^{-1}(\cos (c+d x))}{8 a^6 d}-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}+\frac{\left (4 b \left (2 a^4-7 a^2 b^2+5 b^4\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^6 d}\\ &=-\frac{2 b \left (2 a^4-7 a^2 b^2+5 b^4\right ) \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{a^6 \sqrt{a^2-b^2} d}-\frac{\left (3 a^4-36 a^2 b^2+40 b^4\right ) \tanh ^{-1}(\cos (c+d x))}{8 a^6 d}-\frac{b \left (11 a^2-15 b^2\right ) \cot (c+d x)}{3 a^5 d}+\frac{\left (13 a^2-20 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac{\left (3 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a^3 b d}+\frac{\left (4 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{4 a^2 b d (a+b \sin (c+d x))}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\\ \end{align*}

Mathematica [A]  time = 6.26046, size = 496, normalized size = 1.7 \[ \frac{\left (5 a^2-12 b^2\right ) \csc ^2\left (\frac{1}{2} (c+d x)\right )}{32 a^4 d}+\frac{\left (12 b^2-5 a^2\right ) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{32 a^4 d}+\frac{\left (-36 a^2 b^2+3 a^4+40 b^4\right ) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )}{8 a^6 d}+\frac{\left (36 a^2 b^2-3 a^4-40 b^4\right ) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )}{8 a^6 d}+\frac{b^4 \cos (c+d x)-a^2 b^2 \cos (c+d x)}{a^5 d (a+b \sin (c+d x))}-\frac{2 \csc \left (\frac{1}{2} (c+d x)\right ) \left (2 a^2 b \cos \left (\frac{1}{2} (c+d x)\right )-3 b^3 \cos \left (\frac{1}{2} (c+d x)\right )\right )}{3 a^5 d}+\frac{2 \sec \left (\frac{1}{2} (c+d x)\right ) \left (2 a^2 b \sin \left (\frac{1}{2} (c+d x)\right )-3 b^3 \sin \left (\frac{1}{2} (c+d x)\right )\right )}{3 a^5 d}-\frac{2 b \left (-7 a^2 b^2+2 a^4+5 b^4\right ) \tan ^{-1}\left (\frac{\sec \left (\frac{1}{2} (c+d x)\right ) \left (a \sin \left (\frac{1}{2} (c+d x)\right )+b \cos \left (\frac{1}{2} (c+d x)\right )\right )}{\sqrt{a^2-b^2}}\right )}{a^6 d \sqrt{a^2-b^2}}+\frac{b \cot \left (\frac{1}{2} (c+d x)\right ) \csc ^2\left (\frac{1}{2} (c+d x)\right )}{12 a^3 d}-\frac{b \tan \left (\frac{1}{2} (c+d x)\right ) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{12 a^3 d}-\frac{\csc ^4\left (\frac{1}{2} (c+d x)\right )}{64 a^2 d}+\frac{\sec ^4\left (\frac{1}{2} (c+d x)\right )}{64 a^2 d} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(Cot[c + d*x]^4*Csc[c + d*x])/(a + b*Sin[c + d*x])^2,x]

[Out]

(-2*b*(2*a^4 - 7*a^2*b^2 + 5*b^4)*ArcTan[(Sec[(c + d*x)/2]*(b*Cos[(c + d*x)/2] + a*Sin[(c + d*x)/2]))/Sqrt[a^2
 - b^2]])/(a^6*Sqrt[a^2 - b^2]*d) - (2*(2*a^2*b*Cos[(c + d*x)/2] - 3*b^3*Cos[(c + d*x)/2])*Csc[(c + d*x)/2])/(
3*a^5*d) + ((5*a^2 - 12*b^2)*Csc[(c + d*x)/2]^2)/(32*a^4*d) + (b*Cot[(c + d*x)/2]*Csc[(c + d*x)/2]^2)/(12*a^3*
d) - Csc[(c + d*x)/2]^4/(64*a^2*d) + ((-3*a^4 + 36*a^2*b^2 - 40*b^4)*Log[Cos[(c + d*x)/2]])/(8*a^6*d) + ((3*a^
4 - 36*a^2*b^2 + 40*b^4)*Log[Sin[(c + d*x)/2]])/(8*a^6*d) + ((-5*a^2 + 12*b^2)*Sec[(c + d*x)/2]^2)/(32*a^4*d)
+ Sec[(c + d*x)/2]^4/(64*a^2*d) + (2*Sec[(c + d*x)/2]*(2*a^2*b*Sin[(c + d*x)/2] - 3*b^3*Sin[(c + d*x)/2]))/(3*
a^5*d) + (-(a^2*b^2*Cos[c + d*x]) + b^4*Cos[c + d*x])/(a^5*d*(a + b*Sin[c + d*x])) - (b*Sec[(c + d*x)/2]^2*Tan
[(c + d*x)/2])/(12*a^3*d)

________________________________________________________________________________________

Maple [B]  time = 0.189, size = 634, normalized size = 2.2 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^4*csc(d*x+c)^5/(a+b*sin(d*x+c))^2,x)

[Out]

1/64/d/a^2*tan(1/2*d*x+1/2*c)^4-1/12/d/a^3*tan(1/2*d*x+1/2*c)^3*b-1/8/d/a^2*tan(1/2*d*x+1/2*c)^2+3/8/d/a^4*b^2
*tan(1/2*d*x+1/2*c)^2+5/4/d/a^3*tan(1/2*d*x+1/2*c)*b-2/d/a^5*b^3*tan(1/2*d*x+1/2*c)-2/d*b^3/a^4/(tan(1/2*d*x+1
/2*c)^2*a+2*tan(1/2*d*x+1/2*c)*b+a)*tan(1/2*d*x+1/2*c)+2/d*b^5/a^6/(tan(1/2*d*x+1/2*c)^2*a+2*tan(1/2*d*x+1/2*c
)*b+a)*tan(1/2*d*x+1/2*c)-2/d/a^3/(tan(1/2*d*x+1/2*c)^2*a+2*tan(1/2*d*x+1/2*c)*b+a)*b^2+2/d*b^4/a^5/(tan(1/2*d
*x+1/2*c)^2*a+2*tan(1/2*d*x+1/2*c)*b+a)-4/d/a^2*b/(a^2-b^2)^(1/2)*arctan(1/2*(2*a*tan(1/2*d*x+1/2*c)+2*b)/(a^2
-b^2)^(1/2))+14/d*b^3/a^4/(a^2-b^2)^(1/2)*arctan(1/2*(2*a*tan(1/2*d*x+1/2*c)+2*b)/(a^2-b^2)^(1/2))-10/d*b^5/a^
6/(a^2-b^2)^(1/2)*arctan(1/2*(2*a*tan(1/2*d*x+1/2*c)+2*b)/(a^2-b^2)^(1/2))-1/64/d/a^2/tan(1/2*d*x+1/2*c)^4+1/8
/d/a^2/tan(1/2*d*x+1/2*c)^2-3/8/d/a^4/tan(1/2*d*x+1/2*c)^2*b^2+3/8/d/a^2*ln(tan(1/2*d*x+1/2*c))-9/2/d/a^4*ln(t
an(1/2*d*x+1/2*c))*b^2+5/d/a^6*ln(tan(1/2*d*x+1/2*c))*b^4+1/12/d/a^3*b/tan(1/2*d*x+1/2*c)^3-5/4/d*b/a^3/tan(1/
2*d*x+1/2*c)+2/d*b^3/a^5/tan(1/2*d*x+1/2*c)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^4*csc(d*x+c)^5/(a+b*sin(d*x+c))^2,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [B]  time = 4.6618, size = 3688, normalized size = 12.63 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^4*csc(d*x+c)^5/(a+b*sin(d*x+c))^2,x, algorithm="fricas")

[Out]

[-1/48*(16*(11*a^3*b^2 - 15*a*b^4)*cos(d*x + c)^5 + 2*(15*a^5 - 196*a^3*b^2 + 240*a*b^4)*cos(d*x + c)^3 + 24*(
(2*a^3*b - 5*a*b^3)*cos(d*x + c)^4 + 2*a^3*b - 5*a*b^3 - 2*(2*a^3*b - 5*a*b^3)*cos(d*x + c)^2 + ((2*a^2*b^2 -
5*b^4)*cos(d*x + c)^4 + 2*a^2*b^2 - 5*b^4 - 2*(2*a^2*b^2 - 5*b^4)*cos(d*x + c)^2)*sin(d*x + c))*sqrt(-a^2 + b^
2)*log(-((2*a^2 - b^2)*cos(d*x + c)^2 - 2*a*b*sin(d*x + c) - a^2 - b^2 - 2*(a*cos(d*x + c)*sin(d*x + c) + b*co
s(d*x + c))*sqrt(-a^2 + b^2))/(b^2*cos(d*x + c)^2 - 2*a*b*sin(d*x + c) - a^2 - b^2)) - 6*(3*a^5 - 36*a^3*b^2 +
 40*a*b^4)*cos(d*x + c) + 3*(3*a^5 - 36*a^3*b^2 + 40*a*b^4 + (3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x + c)^4 -
2*(3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x + c)^2 + (3*a^4*b - 36*a^2*b^3 + 40*b^5 + (3*a^4*b - 36*a^2*b^3 + 40
*b^5)*cos(d*x + c)^4 - 2*(3*a^4*b - 36*a^2*b^3 + 40*b^5)*cos(d*x + c)^2)*sin(d*x + c))*log(1/2*cos(d*x + c) +
1/2) - 3*(3*a^5 - 36*a^3*b^2 + 40*a*b^4 + (3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x + c)^4 - 2*(3*a^5 - 36*a^3*b
^2 + 40*a*b^4)*cos(d*x + c)^2 + (3*a^4*b - 36*a^2*b^3 + 40*b^5 + (3*a^4*b - 36*a^2*b^3 + 40*b^5)*cos(d*x + c)^
4 - 2*(3*a^4*b - 36*a^2*b^3 + 40*b^5)*cos(d*x + c)^2)*sin(d*x + c))*log(-1/2*cos(d*x + c) + 1/2) - 2*((49*a^4*
b - 60*a^2*b^3)*cos(d*x + c)^3 - 3*(13*a^4*b - 20*a^2*b^3)*cos(d*x + c))*sin(d*x + c))/(a^7*d*cos(d*x + c)^4 -
 2*a^7*d*cos(d*x + c)^2 + a^7*d + (a^6*b*d*cos(d*x + c)^4 - 2*a^6*b*d*cos(d*x + c)^2 + a^6*b*d)*sin(d*x + c)),
 -1/48*(16*(11*a^3*b^2 - 15*a*b^4)*cos(d*x + c)^5 + 2*(15*a^5 - 196*a^3*b^2 + 240*a*b^4)*cos(d*x + c)^3 - 48*(
(2*a^3*b - 5*a*b^3)*cos(d*x + c)^4 + 2*a^3*b - 5*a*b^3 - 2*(2*a^3*b - 5*a*b^3)*cos(d*x + c)^2 + ((2*a^2*b^2 -
5*b^4)*cos(d*x + c)^4 + 2*a^2*b^2 - 5*b^4 - 2*(2*a^2*b^2 - 5*b^4)*cos(d*x + c)^2)*sin(d*x + c))*sqrt(a^2 - b^2
)*arctan(-(a*sin(d*x + c) + b)/(sqrt(a^2 - b^2)*cos(d*x + c))) - 6*(3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x + c
) + 3*(3*a^5 - 36*a^3*b^2 + 40*a*b^4 + (3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x + c)^4 - 2*(3*a^5 - 36*a^3*b^2
+ 40*a*b^4)*cos(d*x + c)^2 + (3*a^4*b - 36*a^2*b^3 + 40*b^5 + (3*a^4*b - 36*a^2*b^3 + 40*b^5)*cos(d*x + c)^4 -
 2*(3*a^4*b - 36*a^2*b^3 + 40*b^5)*cos(d*x + c)^2)*sin(d*x + c))*log(1/2*cos(d*x + c) + 1/2) - 3*(3*a^5 - 36*a
^3*b^2 + 40*a*b^4 + (3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x + c)^4 - 2*(3*a^5 - 36*a^3*b^2 + 40*a*b^4)*cos(d*x
 + c)^2 + (3*a^4*b - 36*a^2*b^3 + 40*b^5 + (3*a^4*b - 36*a^2*b^3 + 40*b^5)*cos(d*x + c)^4 - 2*(3*a^4*b - 36*a^
2*b^3 + 40*b^5)*cos(d*x + c)^2)*sin(d*x + c))*log(-1/2*cos(d*x + c) + 1/2) - 2*((49*a^4*b - 60*a^2*b^3)*cos(d*
x + c)^3 - 3*(13*a^4*b - 20*a^2*b^3)*cos(d*x + c))*sin(d*x + c))/(a^7*d*cos(d*x + c)^4 - 2*a^7*d*cos(d*x + c)^
2 + a^7*d + (a^6*b*d*cos(d*x + c)^4 - 2*a^6*b*d*cos(d*x + c)^2 + a^6*b*d)*sin(d*x + c))]

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**4*csc(d*x+c)**5/(a+b*sin(d*x+c))**2,x)

[Out]

Timed out

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Giac [A]  time = 1.39535, size = 622, normalized size = 2.13 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^4*csc(d*x+c)^5/(a+b*sin(d*x+c))^2,x, algorithm="giac")

[Out]

1/192*(24*(3*a^4 - 36*a^2*b^2 + 40*b^4)*log(abs(tan(1/2*d*x + 1/2*c)))/a^6 - 384*(2*a^4*b - 7*a^2*b^3 + 5*b^5)
*(pi*floor(1/2*(d*x + c)/pi + 1/2)*sgn(a) + arctan((a*tan(1/2*d*x + 1/2*c) + b)/sqrt(a^2 - b^2)))/(sqrt(a^2 -
b^2)*a^6) - 384*(a^2*b^3*tan(1/2*d*x + 1/2*c) - b^5*tan(1/2*d*x + 1/2*c) + a^3*b^2 - a*b^4)/((a*tan(1/2*d*x +
1/2*c)^2 + 2*b*tan(1/2*d*x + 1/2*c) + a)*a^6) + (3*a^6*tan(1/2*d*x + 1/2*c)^4 - 16*a^5*b*tan(1/2*d*x + 1/2*c)^
3 - 24*a^6*tan(1/2*d*x + 1/2*c)^2 + 72*a^4*b^2*tan(1/2*d*x + 1/2*c)^2 + 240*a^5*b*tan(1/2*d*x + 1/2*c) - 384*a
^3*b^3*tan(1/2*d*x + 1/2*c))/a^8 - (150*a^4*tan(1/2*d*x + 1/2*c)^4 - 1800*a^2*b^2*tan(1/2*d*x + 1/2*c)^4 + 200
0*b^4*tan(1/2*d*x + 1/2*c)^4 + 240*a^3*b*tan(1/2*d*x + 1/2*c)^3 - 384*a*b^3*tan(1/2*d*x + 1/2*c)^3 - 24*a^4*ta
n(1/2*d*x + 1/2*c)^2 + 72*a^2*b^2*tan(1/2*d*x + 1/2*c)^2 - 16*a^3*b*tan(1/2*d*x + 1/2*c) + 3*a^4)/(a^6*tan(1/2
*d*x + 1/2*c)^4))/d